This is a tournament to see which Penitatas is unpopular.
Rules:
1. You vote for the one you want to spare. 2. The one with the most votes is safe from elimination. 3. The others advances to the next round 4. Every round will have a question and the first person to give the correct answer nets you a second vote to either put on the same character or give it to another one. 5. In case of a tie, both tying characters will be spared.
Hi Rouge2 :D!I know somebody gave out the answer and I knew that it was Perci since kadeathnas gave the answer out just now X3 and ^_^, but thanks for letting me try to get to the first round of this contest/tournament at least for myself :3. But I do still get to vote even if I didn't make it to answer the question in time due to someone getting there before me right =3? Let me know Rouge2 =D, and we'll see what we can do about it soon :3 and ;3. I'll try for another question in round 2 soon ^_^, but thanks for letting me try to get to the first round and the question despite me being busy and all for sure :3 and ;3. *Hugs.*.
Bigd33309
Hi *Rouge2* :D!I know somebody gave out the answer and I knew that it was Perci since *kadeathnas*
Very well then I would rather have the one vote option in case I couldn't get to answer the questions on time due to me being busy and all for myself Rouge2 X3 and ^_^, and also I would say this to you "One is enough." and I'll make my best choice now for you then without being upset about the question thing now and still make my vote count too :3 and =3. Since I was torn between either Mei-ying or Karlina or even someone else, I will go with my own gut feeling and best option and go with the best panda bear character for my vote since I like bears so much X3 and :3. My vote is for Mei-ying =3. Thanks Rouge2 :D, and lots of luck to the survivors and answer the questions or not for myself I'll take whatever option for myself instead :3 and ;3. *Hugs and nuzzles =3 and ;3.*.
Bigd33309
Very well then I would rather have the one vote option in case I couldn't get to answer the question